Given an integer array nums
, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.
Follow up: If you have figured out the O(n)
solution, try coding another solution using the divide and conquer approach, which is more subtle.
Example 1:
Input: nums = [-2,1,-3,4,-1,2,1,-5,4]
Output: 6
Explanation: [4,-1,2,1] has the largest sum = 6.
Example 2:
Input: nums = [1]
Output: 1
Example 3:
Input: nums = [0]
Output: 0
Example 4:
Input: nums = [-1]
Output: -1
Example 5:
Input: nums = [-2147483647]
Output: -2147483647
Code:
#define MAX(a,b) ((a>b)?a:b)int maxSubArray(int* nums, int numsSize){
int l, r,sum=0,max=INT_MIN;
for(l=0;l<numsSize;l++){
sum=0;
for(r=l;r<numsSize;r++){
sum+=nums[r];
//printf("l:%dr:%dsum:%d\n",l,r,sum);
max=MAX(max,sum);
}
}
return max;
}
Input:
[-2,1,-3,4,-1,2,1,-5,4]
Output:
6