Given a binary array, find the maximum number of consecutive 1s in this array.
Example 1:
Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
The maximum number of consecutive 1s is 3.
Note:
- The input array will only contain
0
and1
. - The length of input array is a positive integer and will not exceed 10,000
Input:
[1,0,1,1,0,1]
My Code:
int findMaxConsecutiveOnes(int* nums, int numsSize){
int count=0,max=0;
for(int i=0;i<numsSize;i++){
if(nums[i]==1){
count=count+1;
if(count>max){
max=count;
}
}
else{
count=0;
}
printf("count:%d\n",count);
printf("max:%d\n\n",max);
}
return max;
}
Output:
count:1
max:1
count:0
max:1
count:1
max:1
count:2
max:2
count:0
max:2
count:1
max:2
Your answer(return value):
2